Using KCL, if three currents enter a node: 5A, 3A, and 2A, what is the current l

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Question: Using KCL, if three currents enter a node: 5A, 3A, and 2A, what is the current leaving the node?

Options:

Correct Answer: 10A

Solution:

According to KCL, Iin = Iout; 5A + 3A + 2A = Iout; Iout = 10A.

Using KCL, if three currents enter a node: 5A, 3A, and 2A, what is the current leaving the node?

Using KCL, if three currents enter a node: 5A, 3A, and 2A, what is the current leaving the node?

Step 1: Identify the currents entering the node. In this case, the currents are 5A, 3A, and 2A.
Step 2: According to Kirchhoff's Current Law (KCL), the total current entering a node must equal the total current leaving the node.
Step 3: Add the currents entering the node: 5A + 3A + 2A.
Step 4: Calculate the sum: 5A + 3A = 8A, then 8A + 2A = 10A.
Step 5: Set the total current entering equal to the current leaving the node: Iin = Iout.
Step 6: Since the total current entering is 10A, we have Iout = 10A.

Kirchhoff's Current Law (KCL) – KCL states that the total current entering a node must equal the total current leaving the node.