In a series circuit with a 9V battery and two resistors (3Ω and 6Ω), what is the
Practice Questions
Q1
In a series circuit with a 9V battery and two resistors (3Ω and 6Ω), what is the current flowing through the circuit?
1A
2A
3A
4A
Questions & Step-by-Step Solutions
In a series circuit with a 9V battery and two resistors (3Ω and 6Ω), what is the current flowing through the circuit?
Step 1: Identify the components in the circuit. We have a 9V battery and two resistors: one with a resistance of 3Ω and another with a resistance of 6Ω.
Step 2: Calculate the total resistance in the circuit. Since this is a series circuit, we add the resistances together: 3Ω + 6Ω = 9Ω.
Step 3: Use Ohm's Law to find the current. Ohm's Law states that current (I) is equal to voltage (V) divided by resistance (R). Here, V = 9V and R = 9Ω.
Step 4: Substitute the values into the formula: I = 9V / 9Ω.
