In a parallel circuit with two resistors of 6Ω and 3Ω, what is the equivalent re

₹0.0

Question: In a parallel circuit with two resistors of 6Ω and 3Ω, what is the equivalent resistance?

Options:

Correct Answer: 2Ω

Solution:

The equivalent resistance R_eq = 1 / (1/R1 + 1/R2) = 1 / (1/6 + 1/3) = 1 / (1/6 + 2/6) = 1 / (3/6) = 2Ω.

In a parallel circuit with two resistors of 6Ω and 3Ω, what is the equivalent resistance?

In a parallel circuit with two resistors of 6Ω and 3Ω, what is the equivalent resistance?

Step 1: Identify the resistors in the parallel circuit. We have R1 = 6Ω and R2 = 3Ω.
Step 2: Use the formula for equivalent resistance in a parallel circuit: R_eq = 1 / (1/R1 + 1/R2).
Step 3: Substitute the values of R1 and R2 into the formula: R_eq = 1 / (1/6 + 1/3).
Step 4: Convert 1/3 to a fraction with a common denominator: 1/3 = 2/6.
Step 5: Now the equation looks like this: R_eq = 1 / (1/6 + 2/6).
Step 6: Add the fractions: 1/6 + 2/6 = 3/6.
Step 7: Now the equation is: R_eq = 1 / (3/6).
Step 8: To divide by a fraction, multiply by its reciprocal: R_eq = 1 * (6/3).
Step 9: Simplify: R_eq = 6/3 = 2Ω.

Equivalent Resistance in Parallel Circuits – The method to calculate the total resistance in a parallel circuit using the formula R_eq = 1 / (1/R1 + 1/R2).