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In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω,

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Question: In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω, what is the total resistance?

Options:

  1. 2Ω
  2. 4Ω
  3. 1.5Ω
  4. 9Ω

Correct Answer: 2Ω

Solution: 

The total resistance (R_total) in a parallel circuit is calculated using 1/R_total = 1/R1 + 1/R2. Here, 1/R_total = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, so R_total = 2Ω.

In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω,

Practice Questions

Q1
In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω, what is the total resistance?
  1. 2Ω
  2. 4Ω
  3. 1.5Ω
  4. 9Ω

Questions & Step-by-Step Solutions

In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω, what is the total resistance?
  • Step 1: Identify the resistances in the parallel circuit. We have R1 = 6Ω and R2 = 3Ω.
  • Step 2: Use the formula for total resistance in a parallel circuit: 1/R_total = 1/R1 + 1/R2.
  • Step 3: Substitute the values into the formula: 1/R_total = 1/6 + 1/3.
  • Step 4: Convert 1/3 to have a common denominator with 1/6. This gives us 1/3 = 2/6.
  • Step 5: Now add the fractions: 1/6 + 2/6 = 3/6.
  • Step 6: To find R_total, take the reciprocal of 3/6. This means R_total = 6/3 = 2Ω.
  • Parallel Circuit Resistance – In a parallel circuit, the total resistance is found using the formula 1/R_total = 1/R1 + 1/R2, which accounts for the reciprocal nature of resistances in parallel.
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