In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω,

In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω, what is the total resistance?

In a parallel circuit, if one branch has a resistance of 6Ω and another has 3Ω, what is the total resistance?

Step 1: Identify the resistances in the parallel circuit. We have R1 = 6Ω and R2 = 3Ω.
Step 2: Use the formula for total resistance in a parallel circuit: 1/R_total = 1/R1 + 1/R2.
Step 3: Substitute the values into the formula: 1/R_total = 1/6 + 1/3.
Step 4: Convert 1/3 to have a common denominator with 1/6. This gives us 1/3 = 2/6.
Step 5: Now add the fractions: 1/6 + 2/6 = 3/6.
Step 6: To find R_total, take the reciprocal of 3/6. This means R_total = 6/3 = 2Ω.

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