In triangle ABC, if the lengths of sides a, b, and c are 7, 24, and 25 respectively, what is the area of the triangle?

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Q: In triangle ABC, if the lengths of sides a, b, and c are 7, 24, and 25 respectively, what is the area of the triangle?

Solution: Using Heron's formula, s = (7 + 24 + 25)/2 = 28. Area = √[s(s-a)(s-b)(s-c)] = √[28(28-7)(28-24)(28-25)] = √[28*21*4*3] = 84.

Steps: 8

Step 1: Identify the lengths of the sides of the triangle. Here, side a = 7, side b = 24, and side c = 25.
Step 2: Calculate the semi-perimeter (s) of the triangle using the formula s = (a + b + c) / 2. So, s = (7 + 24 + 25) / 2 = 28.
Step 3: Use Heron's formula to find the area of the triangle. The formula is Area = √[s(s-a)(s-b)(s-c)].
Step 4: Substitute the values into the formula. We have Area = √[28(28-7)(28-24)(28-25)].
Step 5: Calculate each part inside the square root. First, calculate (28-7) = 21, (28-24) = 4, and (28-25) = 3.
Step 6: Now substitute these values back into the formula: Area = √[28 * 21 * 4 * 3].
Step 7: Multiply the numbers inside the square root: 28 * 21 = 588, then 588 * 4 = 2352, and finally 2352 * 3 = 7056.
Step 8: Take the square root of 7056 to find the area. Area = √7056 = 84.