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What is the equation of the line that is perpendicular to y = 3x + 2 and passes through the point (1, 1)? (2022)

Practice Questions

1 question
Q1
What is the equation of the line that is perpendicular to y = 3x + 2 and passes through the point (1, 1)? (2022)
  1. y = -1/3x + 4/3
  2. y = 3x - 2
  3. y = -3x + 4
  4. y = 1/3x + 2/3

Questions & Step-by-step Solutions

1 item
Q
Q: What is the equation of the line that is perpendicular to y = 3x + 2 and passes through the point (1, 1)? (2022)
Solution: The slope of the perpendicular line is -1/3. Using point-slope form: y - 1 = -1/3(x - 1) gives y = -1/3x + 4/3.
Steps: 0

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