What is the total capacitance of two capacitors, C1 = 3μF and C2 = 6μF, connecte

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Question: What is the total capacitance of two capacitors, C1 = 3μF and C2 = 6μF, connected in series? (2022)

Options:

Correct Answer: 2μF

Exam Year: 2022

Solution:

The formula for total capacitance in series is 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/3 + 1/6 = 1/2, so C_eq = 2μF.

What is the total capacitance of two capacitors, C1 = 3μF and C2 = 6μF, connected in series? (2022)

What is the total capacitance of two capacitors, C1 = 3μF and C2 = 6μF, connected in series? (2022)

Step 1: Identify the values of the capacitors. Here, C1 = 3μF and C2 = 6μF.
Step 2: Write down the formula for total capacitance in series: 1/C_eq = 1/C1 + 1/C2.
Step 3: Substitute the values of C1 and C2 into the formula: 1/C_eq = 1/3 + 1/6.
Step 4: Find a common denominator to add the fractions. The common denominator for 3 and 6 is 6.
Step 5: Rewrite the fractions: 1/3 = 2/6, so now we have 1/C_eq = 2/6 + 1/6.
Step 6: Add the fractions: 2/6 + 1/6 = 3/6.
Step 7: Now we have 1/C_eq = 3/6. To find C_eq, take the reciprocal: C_eq = 6/3.
Step 8: Simplify the result: C_eq = 2μF.

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