What is the equivalent resistance of two resistors, R1 = 4Ω and R2 = 6Ω, in para

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Question: What is the equivalent resistance of two resistors, R1 = 4Ω and R2 = 6Ω, in parallel? (2022)

Options:

Correct Answer: 2.4Ω

Exam Year: 2022

Solution:

The formula for equivalent resistance in parallel is 1/R_eq = 1/R1 + 1/R2. Thus, 1/R_eq = 1/4 + 1/6 = 5/12, so R_eq = 12/5 = 2.4Ω.

What is the equivalent resistance of two resistors, R1 = 4Ω and R2 = 6Ω, in parallel? (2022)

What is the equivalent resistance of two resistors, R1 = 4Ω and R2 = 6Ω, in parallel? (2022)

Step 1: Identify the values of the resistors. Here, R1 = 4Ω and R2 = 6Ω.
Step 2: Write down the formula for equivalent resistance in parallel: 1/R_eq = 1/R1 + 1/R2.
Step 3: Substitute the values of R1 and R2 into the formula: 1/R_eq = 1/4 + 1/6.
Step 4: Find a common denominator to add the fractions. The common denominator for 4 and 6 is 12.
Step 5: Convert the fractions: 1/4 = 3/12 and 1/6 = 2/12.
Step 6: Add the fractions: 1/R_eq = 3/12 + 2/12 = 5/12.
Step 7: To find R_eq, take the reciprocal of 5/12: R_eq = 12/5.
Step 8: Simplify 12/5 to get the final answer: R_eq = 2.4Ω.

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