In a mixture of two liquids, if the first liquid is 25% alcohol and the second i
Practice Questions
Q1
In a mixture of two liquids, if the first liquid is 25% alcohol and the second is 75% alcohol, what is the overall percentage of alcohol in a 10-liter mixture containing 4 liters of the first liquid?
45%
50%
55%
60%
Questions & Step-by-Step Solutions
In a mixture of two liquids, if the first liquid is 25% alcohol and the second is 75% alcohol, what is the overall percentage of alcohol in a 10-liter mixture containing 4 liters of the first liquid?
Step 1: Identify the volumes of the two liquids in the mixture. We have 4 liters of the first liquid and the total mixture is 10 liters, so the second liquid is 10 - 4 = 6 liters.
Step 2: Calculate the amount of alcohol in the first liquid. The first liquid is 25% alcohol, so we calculate 25% of 4 liters: 0.25 * 4 = 1 liter of alcohol.
Step 3: Calculate the amount of alcohol in the second liquid. The second liquid is 75% alcohol, so we calculate 75% of 6 liters: 0.75 * 6 = 4.5 liters of alcohol.
Step 4: Add the amounts of alcohol from both liquids to find the total alcohol in the mixture: 1 liter (from the first liquid) + 4.5 liters (from the second liquid) = 5.5 liters of alcohol.
Step 5: Calculate the overall percentage of alcohol in the mixture. The total volume of the mixture is 10 liters, so we calculate the percentage: (5.5 liters of alcohol / 10 liters of mixture) * 100 = 55%.
