A bag contains 3 red and 2 blue balls. If one ball is drawn at random, what is the probability that it is red given that it is not blue?
Practice Questions
1 question
Q1
A bag contains 3 red and 2 blue balls. If one ball is drawn at random, what is the probability that it is red given that it is not blue?
1/2
3/5
2/5
3/4
The total number of balls that are not blue is 3 (red). The probability of drawing a red ball given that it is not blue is 3/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A bag contains 3 red and 2 blue balls. If one ball is drawn at random, what is the probability that it is red given that it is not blue?
Solution: The total number of balls that are not blue is 3 (red). The probability of drawing a red ball given that it is not blue is 3/5.
Steps: 5
Step 1: Identify the total number of balls in the bag. There are 3 red balls and 2 blue balls, so the total is 3 + 2 = 5 balls.
Step 2: Determine how many balls are not blue. Since there are 2 blue balls, the balls that are not blue are the 3 red balls.
Step 3: Count the number of favorable outcomes. The favorable outcome is drawing a red ball, and there are 3 red balls.
Step 4: Calculate the total number of outcomes that are not blue. Since there are 3 red balls and 2 blue balls, the total number of balls that are not blue is 3 (the red balls).
Step 5: Find the probability of drawing a red ball given that it is not blue. The probability is the number of red balls (3) divided by the total number of balls that are not blue (3). So, the probability is 3/3 = 1.
