For a second-order system, what is the damping ratio if the poles are located at

Practice Questions

Q1
For a second-order system, what is the damping ratio if the poles are located at -2 ± j2?
  1. 0.5
  2. 1
  3. 0.707
  4. 0

Questions & Step-by-Step Solutions

For a second-order system, what is the damping ratio if the poles are located at -2 ± j2?
  • Step 1: Identify the poles of the system, which are given as -2 ± j2.
  • Step 2: From the poles, determine the real part (σ) and the imaginary part (ω). Here, σ = -2 and ω = 2.
  • Step 3: Since we need the damping ratio (ζ), we use the formula ζ = -σ / √(σ² + ω²).
  • Step 4: Calculate σ², which is (-2)² = 4.
  • Step 5: Calculate ω², which is (2)² = 4.
  • Step 6: Add σ² and ω² together: 4 + 4 = 8.
  • Step 7: Take the square root of the sum: √8 = 2.828.
  • Step 8: Substitute σ and the square root value into the damping ratio formula: ζ = -(-2) / 2.828.
  • Step 9: Simplify the equation: ζ = 2 / 2.828.
  • Step 10: Calculate the final value: ζ ≈ 0.707.
  • Damping Ratio – The damping ratio (ζ) is a measure of how oscillations in a system decay after a disturbance, calculated using the real and imaginary parts of the poles.
  • Poles of a System – The poles of a second-order system are complex numbers that determine the system's stability and response characteristics.
  • Second-Order System Dynamics – Understanding the behavior of second-order systems, including how damping affects the transient response.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely