What is the time constant of a system with a transfer function G(s) = 5/(2s + 5)

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Question: What is the time constant of a system with a transfer function G(s) = 5/(2s + 5)?

Options:

Correct Answer: 0.4

Solution:

The time constant T is given by the coefficient of s in the denominator, which is 2. Therefore, T = 5/2 = 0.4.

What is the time constant of a system with a transfer function G(s) = 5/(2s + 5)?

What is the time constant of a system with a transfer function G(s) = 5/(2s + 5)?

Step 1: Identify the transfer function G(s) = 5/(2s + 5).
Step 2: Look at the denominator of the transfer function, which is 2s + 5.
Step 3: Find the coefficient of s in the denominator. Here, the coefficient is 2.
Step 4: The time constant T is calculated as T = 5 divided by the coefficient of s.
Step 5: Substitute the coefficient into the formula: T = 5/2.
Step 6: Calculate the value: T = 2.5.

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