In an AC circuit, what is the impedance of a circuit with a resistor of 4Ω and a

₹0.0

Question: In an AC circuit, what is the impedance of a circuit with a resistor of 4Ω and an inductor with a reactance of 3Ω?

Options:

Correct Answer: 7Ω

Solution:

Impedance (Z) in a series circuit is calculated using Z = √(R^2 + X_L^2). Here, Z = √(4^2 + 3^2) = √(16 + 9) = √25 = 5Ω.

In an AC circuit, what is the impedance of a circuit with a resistor of 4Ω and an inductor with a reactance of 3Ω?

In an AC circuit, what is the impedance of a circuit with a resistor of 4Ω and an inductor with a reactance of 3Ω?

Step 1: Identify the values given in the problem. We have a resistor (R) with a value of 4Ω and an inductor with a reactance (X_L) of 3Ω.
Step 2: Write down the formula for impedance (Z) in a series circuit, which is Z = √(R^2 + X_L^2).
Step 3: Substitute the values of R and X_L into the formula. This gives us Z = √(4^2 + 3^2).
Step 4: Calculate R^2, which is 4^2 = 16.
Step 5: Calculate X_L^2, which is 3^2 = 9.
Step 6: Add the results from Step 4 and Step 5 together: 16 + 9 = 25.
Step 7: Take the square root of the sum from Step 6: √25 = 5.
Step 8: Conclude that the impedance (Z) of the circuit is 5Ω.

Impedance in AC Circuits – Impedance is the total opposition to current flow in an AC circuit, combining resistance and reactance.
Series Circuit Calculations – In a series circuit, the total impedance is calculated using the Pythagorean theorem, considering both resistance and inductive reactance.