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In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is t

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Question: In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is the current flowing through the circuit?

Options:

  1. 0.8 A
  2. 1.2 A
  3. 2 A
  4. 3 A

Correct Answer: 1.2 A

Solution: 

Total resistance R = 4Ω + 6Ω = 10Ω. Using Ohm\'s Law, I = V / R = 12V / 10Ω = 1.2 A.

In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is t

Practice Questions

Q1
In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is the current flowing through the circuit?
  1. 0.8 A
  2. 1.2 A
  3. 2 A
  4. 3 A

Questions & Step-by-Step Solutions

In a series circuit with a 12V battery and two resistors of 4Ω and 6Ω, what is the current flowing through the circuit?
  • Step 1: Identify the voltage of the battery, which is 12V.
  • Step 2: Identify the resistors in the circuit, which are 4Ω and 6Ω.
  • Step 3: Calculate the total resistance in the circuit by adding the resistances together: 4Ω + 6Ω = 10Ω.
  • Step 4: Use Ohm's Law to find the current. Ohm's Law states that I = V / R.
  • Step 5: Substitute the values into the formula: I = 12V / 10Ω.
  • Step 6: Calculate the current: 12V divided by 10Ω equals 1.2 A.
  • Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
  • Series Circuit – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
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