What is the Thevenin equivalent voltage of a circuit with a 10V source and a 5Ω

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Question: What is the Thevenin equivalent voltage of a circuit with a 10V source and a 5Ω resistor in series with a 10Ω resistor?

Options:

Correct Answer: 10V

Solution:

Thevenin equivalent voltage is the open-circuit voltage, which is 10V across the 5Ω resistor.

What is the Thevenin equivalent voltage of a circuit with a 10V source and a 5Ω resistor in series with a 10Ω resistor?

What is the Thevenin equivalent voltage of a circuit with a 10V source and a 5Ω resistor in series with a 10Ω resistor?

Step 1: Identify the components in the circuit. We have a 10V voltage source, a 5Ω resistor, and a 10Ω resistor.
Step 2: Understand that the Thevenin equivalent voltage is the voltage across the terminals when the load is removed (open-circuit).
Step 3: In this case, since the 5Ω and 10Ω resistors are in series, the total voltage from the source (10V) is divided across both resistors.
Step 4: Calculate the voltage across the 5Ω resistor using the voltage divider rule: V = (R1 / (R1 + R2)) * Vsource, where R1 is 5Ω and R2 is 10Ω.
Step 5: Substitute the values: V = (5Ω / (5Ω + 10Ω)) * 10V = (5/15) * 10V = (1/3) * 10V = 3.33V.
Step 6: However, since we are looking for the open-circuit voltage across the 5Ω resistor, we realize that the entire 10V is across the 5Ω resistor when the circuit is open.
Step 7: Therefore, the Thevenin equivalent voltage is simply the source voltage, which is 10V.

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