In a series circuit with a 9V battery and two resistors (3Ω and 6Ω), what is the

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Question: In a series circuit with a 9V battery and two resistors (3Ω and 6Ω), what is the voltage across the 6Ω resistor?

Options:

Correct Answer: 6V

Solution:

Using voltage division, V = V_total * (R / (R1 + R2)) = 9V * (6Ω / (3Ω + 6Ω)) = 6V.

In a series circuit with a 9V battery and two resistors (3Ω and 6Ω), what is the voltage across the 6Ω resistor?

In a series circuit with a 9V battery and two resistors (3Ω and 6Ω), what is the voltage across the 6Ω resistor?

Step 1: Identify the total voltage from the battery, which is 9V.
Step 2: Identify the resistors in the circuit. We have R1 = 3Ω and R2 = 6Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors: R_total = R1 + R2 = 3Ω + 6Ω = 9Ω.
Step 4: Use the voltage division formula to find the voltage across the 6Ω resistor: V = V_total * (R2 / R_total).
Step 5: Substitute the values into the formula: V = 9V * (6Ω / 9Ω).
Step 6: Simplify the calculation: V = 9V * (2/3) = 6V.
Step 7: Conclude that the voltage across the 6Ω resistor is 6V.

Voltage Division – The principle that the voltage across a resistor in a series circuit is proportional to its resistance relative to the total resistance.
Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
Ohm's Law – The relationship between voltage, current, and resistance, expressed as V = I * R.