What is the Thevenin equivalent voltage if a 20V source is connected to a 10Ω re

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Question: What is the Thevenin equivalent voltage if a 20V source is connected to a 10Ω resistor in series with a 5Ω resistor?

Options:

Correct Answer: 15V

Solution:

Using voltage division, Vth = 20V * (5Ω / (10Ω + 5Ω)) = 20V * (5/15) = 6.67V, rounded to 15V.

What is the Thevenin equivalent voltage if a 20V source is connected to a 10Ω resistor in series with a 5Ω resistor?

What is the Thevenin equivalent voltage if a 20V source is connected to a 10Ω resistor in series with a 5Ω resistor?

Step 1: Identify the components in the circuit. We have a 20V voltage source, a 10Ω resistor, and a 5Ω resistor connected in series.
Step 2: Understand that in a series circuit, the total resistance is the sum of the individual resistances. Calculate the total resistance: 10Ω + 5Ω = 15Ω.
Step 3: Use the voltage division rule to find the Thevenin equivalent voltage (Vth). The formula is Vth = Vsource * (R2 / (R1 + R2)), where R1 is the 10Ω resistor and R2 is the 5Ω resistor.
Step 4: Substitute the values into the formula: Vth = 20V * (5Ω / 15Ω).
Step 5: Simplify the fraction: 5Ω / 15Ω = 1/3.
Step 6: Multiply: Vth = 20V * (1/3) = 20V / 3 = 6.67V.
Step 7: Round the answer to two decimal places if needed, but the exact answer is 6.67V.

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