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If a circuit has a Norton equivalent of 2A and a load resistance of 8Ω, what is

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Question: If a circuit has a Norton equivalent of 2A and a load resistance of 8Ω, what is the power delivered to the load?

Options:

  1. 0.5W
  2. 1W
  3. 2W
  4. 4W

Correct Answer: 2W

Solution: 

Power (P) = I^2 * R = (2A)^2 * 8Ω = 4 * 8 = 32W.

If a circuit has a Norton equivalent of 2A and a load resistance of 8Ω, what is

Practice Questions

Q1
If a circuit has a Norton equivalent of 2A and a load resistance of 8Ω, what is the power delivered to the load?
  1. 0.5W
  2. 1W
  3. 2W
  4. 4W

Questions & Step-by-Step Solutions

If a circuit has a Norton equivalent of 2A and a load resistance of 8Ω, what is the power delivered to the load?
  • Step 1: Identify the Norton current (I) which is given as 2A.
  • Step 2: Identify the load resistance (R) which is given as 8Ω.
  • Step 3: Use the power formula for resistive loads: Power (P) = I^2 * R.
  • Step 4: Substitute the values into the formula: P = (2A)^2 * 8Ω.
  • Step 5: Calculate (2A)^2 which equals 4A^2.
  • Step 6: Multiply 4A^2 by 8Ω to find the power: 4 * 8 = 32W.
  • Step 7: Conclude that the power delivered to the load is 32W.
  • Norton Theorem – A method to simplify complex circuits by replacing them with an equivalent current source and parallel resistance.
  • Power Calculation – The formula for calculating power in a resistive load using current and resistance.
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