Question: In a circuit with a Norton equivalent current of 3A and a load resistance of 6Ω, what is the voltage across the load?
Options:
6V
9V
12V
18V
Correct Answer: 12V
Solution:
Using V = I * R, V = 3A * 6Ω = 18V.
In a circuit with a Norton equivalent current of 3A and a load resistance of 6Ω,
Practice Questions
Q1
In a circuit with a Norton equivalent current of 3A and a load resistance of 6Ω, what is the voltage across the load?
6V
9V
12V
18V
Questions & Step-by-Step Solutions
In a circuit with a Norton equivalent current of 3A and a load resistance of 6Ω, what is the voltage across the load?
Step 1: Identify the Norton equivalent current, which is given as 3A.
Step 2: Identify the load resistance, which is given as 6Ω.
Step 3: Use the formula for voltage, which is V = I * R.
Step 4: Substitute the values into the formula: V = 3A * 6Ω.
Step 5: Calculate the result: V = 18V.
Norton Theorem – A method to simplify complex circuits by replacing them with an equivalent current source and parallel resistance.
Ohm's Law – A fundamental principle stating that the voltage across a conductor is directly proportional to the current flowing through it, expressed as V = I * R.
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