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What is the total power dissipated in a circuit with a 24V source and a 4Ω resis

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Question: What is the total power dissipated in a circuit with a 24V source and a 4Ω resistor?

Options:

  1. 6W
  2. 12W
  3. 24W
  4. 48W

Correct Answer: 12W

Solution: 

Power (P) = V^2 / R = 24V^2 / 4Ω = 576 / 4 = 144W.

What is the total power dissipated in a circuit with a 24V source and a 4Ω resis

Practice Questions

Q1
What is the total power dissipated in a circuit with a 24V source and a 4Ω resistor?
  1. 6W
  2. 12W
  3. 24W
  4. 48W

Questions & Step-by-Step Solutions

What is the total power dissipated in a circuit with a 24V source and a 4Ω resistor?
  • Step 1: Identify the voltage (V) in the circuit, which is given as 24 volts.
  • Step 2: Identify the resistance (R) in the circuit, which is given as 4 ohms.
  • Step 3: Use the power formula: Power (P) = V^2 / R.
  • Step 4: Substitute the values into the formula: P = (24V)^2 / 4Ω.
  • Step 5: Calculate (24V)^2, which is 576.
  • Step 6: Divide 576 by 4Ω to find the power: 576 / 4 = 144.
  • Step 7: Conclude that the total power dissipated in the circuit is 144 watts.
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