In a circuit with a 12V source and two resistors (3Ω and 6Ω) in parallel, what i

In a circuit with a 12V source and two resistors (3Ω and 6Ω) in parallel, what is the Norton equivalent current (In) at the terminals?

In a circuit with a 12V source and two resistors (3Ω and 6Ω) in parallel, what is the Norton equivalent current (In) at the terminals?

Step 1: Identify the voltage source in the circuit, which is 12V.
Step 2: Identify the two resistors in parallel, which are 3Ω and 6Ω.
Step 3: Calculate the equivalent resistance (R_eq) of the two resistors using the formula: R_eq = (R1 * R2) / (R1 + R2).
Step 4: Substitute the values into the formula: R_eq = (3Ω * 6Ω) / (3Ω + 6Ω).
Step 5: Calculate the denominator: 3Ω + 6Ω = 9Ω.
Step 6: Calculate the numerator: 3Ω * 6Ω = 18Ω.
Step 7: Now divide the numerator by the denominator: R_eq = 18Ω / 9Ω = 2Ω.
Step 8: Use the equivalent resistance to find the Norton equivalent current (In) using the formula: In = V / R_eq.
Step 9: Substitute the values: In = 12V / 2Ω.
Step 10: Calculate the Norton equivalent current: In = 6A.

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