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In a circuit with a Norton equivalent current of 3A and a load resistance of 1Ω,

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Question: In a circuit with a Norton equivalent current of 3A and a load resistance of 1Ω, what is the voltage across the load?

Options:

  1. 3V
  2. 1V
  3. 0.5V
  4. 6V

Correct Answer: 3V

Solution:

Using Ohm\'s law: V = I * R = 3A * 1Ω = 3V.

In a circuit with a Norton equivalent current of 3A and a load resistance of 1Ω,

Practice Questions

Q1
In a circuit with a Norton equivalent current of 3A and a load resistance of 1Ω, what is the voltage across the load?
  1. 3V
  2. 1V
  3. 0.5V
  4. 6V

Questions & Step-by-Step Solutions

In a circuit with a Norton equivalent current of 3A and a load resistance of 1Ω, what is the voltage across the load?
  • Step 1: Identify the Norton equivalent current, which is given as 3A.
  • Step 2: Identify the load resistance, which is given as 1Ω.
  • Step 3: Use Ohm's law formula, which states that Voltage (V) = Current (I) * Resistance (R).
  • Step 4: Substitute the values into the formula: V = 3A * 1Ω.
  • Step 5: Calculate the voltage: V = 3V.
  • Norton Equivalent Circuit – A representation of a complex circuit as a current source in parallel with a resistor.
  • Ohm's Law – A fundamental principle stating that the current through a conductor between two points is directly proportional to the voltage across the two points.
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