In a parallel circuit with two resistors (4Ω and 6Ω), what is the total equivale

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Question: In a parallel circuit with two resistors (4Ω and 6Ω), what is the total equivalent resistance?

Options:

Correct Answer: 2.4Ω

Solution:

Using the formula for parallel resistors: 1/R_total = 1/4 + 1/6 = 5/12, R_total = 12/5 = 2.4Ω.

In a parallel circuit with two resistors (4Ω and 6Ω), what is the total equivalent resistance?

In a parallel circuit with two resistors (4Ω and 6Ω), what is the total equivalent resistance?

Step 1: Identify the resistors in the parallel circuit. We have two resistors: one is 4Ω and the other is 6Ω.
Step 2: Use the formula for calculating the total equivalent resistance in a parallel circuit: 1/R_total = 1/R1 + 1/R2.
Step 3: Substitute the values of the resistors into the formula: 1/R_total = 1/4 + 1/6.
Step 4: Find a common denominator to add the fractions. The common denominator for 4 and 6 is 12.
Step 5: Rewrite the fractions with the common denominator: 1/4 = 3/12 and 1/6 = 2/12.
Step 6: Add the fractions: 1/R_total = 3/12 + 2/12 = 5/12.
Step 7: To find R_total, take the reciprocal of 5/12: R_total = 12/5.
Step 8: Calculate 12/5 to get the final answer: R_total = 2.4Ω.

Parallel Resistor Calculation – Understanding how to calculate the total equivalent resistance in a parallel circuit using the formula 1/R_total = 1/R1 + 1/R2.