In a circuit with a 12V source and two resistors (3Ω and 6Ω) in series, what is

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Question: In a circuit with a 12V source and two resistors (3Ω and 6Ω) in series, what is the Thevenin equivalent resistance (Rth)?

Options:

Correct Answer: 9Ω

Solution:

Rth = R1 + R2 = 3Ω + 6Ω = 9Ω.

In a circuit with a 12V source and two resistors (3Ω and 6Ω) in series, what is the Thevenin equivalent resistance (Rth)?

In a circuit with a 12V source and two resistors (3Ω and 6Ω) in series, what is the Thevenin equivalent resistance (Rth)?

Step 1: Identify the resistors in the circuit. We have two resistors: R1 = 3Ω and R2 = 6Ω.
Step 2: Understand that when resistors are in series, their total resistance is the sum of their individual resistances.
Step 3: Write the formula for total resistance in series: Rth = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: Rth = 3Ω + 6Ω.
Step 5: Perform the addition: 3Ω + 6Ω = 9Ω.
Step 6: Conclude that the Thevenin equivalent resistance (Rth) is 9Ω.

Thevenin's Theorem – Thevenin's Theorem states that any linear circuit with voltage sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor.
Series Resistors – In a series circuit, the total resistance is the sum of the individual resistances.