What is the Thevenin equivalent voltage if a circuit has a 12V source and a 4Ω r

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Question: What is the Thevenin equivalent voltage if a circuit has a 12V source and a 4Ω resistor in series with a 2Ω load?

Options:

Correct Answer: 8V

Solution:

The Thevenin voltage is the voltage across the load resistor. Using voltage division, V_load = 12V * (2Ω / (4Ω + 2Ω)) = 12V * (1/3) = 4V.

What is the Thevenin equivalent voltage if a circuit has a 12V source and a 4Ω resistor in series with a 2Ω load?

What is the Thevenin equivalent voltage if a circuit has a 12V source and a 4Ω resistor in series with a 2Ω load?

Step 1: Identify the components in the circuit. We have a 12V voltage source, a 4Ω resistor, and a 2Ω load resistor.
Step 2: Recognize that the 4Ω resistor and the 2Ω load resistor are in series.
Step 3: Calculate the total resistance in the series circuit. Total resistance = 4Ω + 2Ω = 6Ω.
Step 4: Use the voltage division rule to find the voltage across the load resistor (2Ω). The formula is V_load = V_source * (R_load / (R_series)).
Step 5: Substitute the values into the formula: V_load = 12V * (2Ω / 6Ω).
Step 6: Simplify the fraction: 2Ω / 6Ω = 1/3.
Step 7: Calculate V_load: V_load = 12V * (1/3) = 4V.
Step 8: Conclude that the Thevenin equivalent voltage is 4V.

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