In a series circuit, if the total voltage is 12V and the resistances are 2Ω and

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Question: In a series circuit, if the total voltage is 12V and the resistances are 2Ω and 4Ω, what is the current flowing through the circuit?

Options:

Correct Answer: 3A

Solution:

Using Ohm\'s Law, the total resistance is 2Ω + 4Ω = 6Ω. The current I = V / R = 12V / 6Ω = 2A.

In a series circuit, if the total voltage is 12V and the resistances are 2Ω and 4Ω, what is the current flowing through the circuit?

In a series circuit, if the total voltage is 12V and the resistances are 2Ω and 4Ω, what is the current flowing through the circuit?

Step 1: Identify the total voltage in the circuit, which is given as 12V.
Step 2: Identify the resistances in the circuit, which are 2Ω and 4Ω.
Step 3: Calculate the total resistance by adding the individual resistances: 2Ω + 4Ω = 6Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that current (I) equals voltage (V) divided by resistance (R).
Step 5: Substitute the values into the formula: I = 12V / 6Ω.
Step 6: Calculate the current: I = 2A.

Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
Series Circuit – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.