Question: In a parallel circuit with two resistors, R1 = 4Ω and R2 = 6Ω, what is the total resistance?
Options:
2.4Ω
10Ω
24Ω
1.5Ω
Correct Answer: 2.4Ω
Solution:
Total resistance R = 1 / (1/R1 + 1/R2) = 1 / (1/4 + 1/6) = 2.4Ω.
In a parallel circuit with two resistors, R1 = 4Ω and R2 = 6Ω, what is the total
Practice Questions
Q1
In a parallel circuit with two resistors, R1 = 4Ω and R2 = 6Ω, what is the total resistance?
2.4Ω
10Ω
24Ω
1.5Ω
Questions & Step-by-Step Solutions
In a parallel circuit with two resistors, R1 = 4Ω and R2 = 6Ω, what is the total resistance?
Step 1: Identify the values of the resistors. Here, R1 = 4Ω and R2 = 6Ω.
Step 2: Use the formula for total resistance in a parallel circuit: R = 1 / (1/R1 + 1/R2).
Step 3: Calculate 1/R1. This is 1/4 = 0.25.
Step 4: Calculate 1/R2. This is 1/6 ≈ 0.1667.
Step 5: Add the two results from Step 3 and Step 4: 0.25 + 0.1667 = 0.4167.
Step 6: Take the reciprocal of the sum from Step 5 to find the total resistance: R = 1 / 0.4167 ≈ 2.4Ω.
Parallel Circuit Resistance – In a parallel circuit, the total resistance is calculated using the formula R_total = 1 / (1/R1 + 1/R2), which accounts for the reciprocal nature of resistances in parallel.
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