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In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω,

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Question: In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω, and 5Ω, what is the current flowing through the circuit?

Options:

  1. 1A
  2. 2A
  3. 3A
  4. 4A

Correct Answer: 2A

Solution: 

Total resistance R = 2 + 3 + 5 = 10Ω. Using Ohm\'s Law, I = V / R = 12V / 10Ω = 1.2A.

In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω,

Practice Questions

Q1
In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω, and 5Ω, what is the current flowing through the circuit?
  1. 1A
  2. 2A
  3. 3A
  4. 4A

Questions & Step-by-Step Solutions

In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω, and 5Ω, what is the current flowing through the circuit?
  • Step 1: Identify the total voltage in the circuit, which is given as 12V.
  • Step 2: Identify the resistances in the circuit, which are 2Ω, 3Ω, and 5Ω.
  • Step 3: Calculate the total resistance by adding the individual resistances: 2Ω + 3Ω + 5Ω.
  • Step 4: Perform the addition: 2 + 3 = 5, then 5 + 5 = 10. So, the total resistance is 10Ω.
  • Step 5: Use Ohm's Law to find the current. Ohm's Law states that I (current) = V (voltage) / R (resistance).
  • Step 6: Substitute the values into the formula: I = 12V / 10Ω.
  • Step 7: Perform the division: 12 divided by 10 equals 1.2. So, the current flowing through the circuit is 1.2A.
  • Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
  • Series Circuit – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
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