In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω,

In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω, and 5Ω, what is the current flowing through the circuit?

In a series circuit, if the total voltage is 12V and the resistances are 2Ω, 3Ω, and 5Ω, what is the current flowing through the circuit?

Step 1: Identify the total voltage in the circuit, which is given as 12V.
Step 2: Identify the resistances in the circuit, which are 2Ω, 3Ω, and 5Ω.
Step 3: Calculate the total resistance by adding the individual resistances: 2Ω + 3Ω + 5Ω.
Step 4: Perform the addition: 2 + 3 = 5, then 5 + 5 = 10. So, the total resistance is 10Ω.
Step 5: Use Ohm's Law to find the current. Ohm's Law states that I (current) = V (voltage) / R (resistance).
Step 6: Substitute the values into the formula: I = 12V / 10Ω.
Step 7: Perform the division: 12 divided by 10 equals 1.2. So, the current flowing through the circuit is 1.2A.

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