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What is the value of (x + y + z)²?
What is the value of (x + y + z)²?
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Practice Questions
1 question
Q1
What is the value of (x + y + z)²?
x² + y² + z²
x² + y² + z² + 2xy + 2yz + 2zx
x² + y² + z² + 3xyz
x² + y² + z² - 2xy - 2yz - 2zx
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(x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx by the expansion of the square of a trinomial.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the value of (x + y + z)²?
Solution:
(x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx by the expansion of the square of a trinomial.
Steps: 6
Show Steps
Step 1: Start with the expression (x + y + z)².
Step 2: Recognize that this is the square of a trinomial, which means we need to expand it.
Step 3: Use the formula for the square of a sum: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca.
Step 4: In our case, let a = x, b = y, and c = z.
Step 5: Substitute x, y, and z into the formula: (x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx.
Step 6: Write down the final expanded form: (x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx.
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