What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the origin?
Practice Questions
1 question
Q1
What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the origin?
y = -1/3x
y = 3x
y = -3x
y = 1/3x
The slope of the given line is 3. The slope of the perpendicular line is -1/3. Thus, the equation is y = -1/3x.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the origin?
Solution: The slope of the given line is 3. The slope of the perpendicular line is -1/3. Thus, the equation is y = -1/3x.
Steps: 4
Step 1: Identify the slope of the given line. The equation is y = 3x + 4, so the slope (m) is 3.
Step 2: Find the slope of the line that is perpendicular to the given line. The slope of a perpendicular line is the negative reciprocal of the original slope. The negative reciprocal of 3 is -1/3.
Step 3: Since the line we want passes through the origin, we know that the y-intercept (b) is 0.
Step 4: Write the equation of the line using the slope and y-intercept. The equation is y = -1/3x.
