What is the equation of the line that is perpendicular to y = 3x + 4 and passes

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Question: What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the origin?

Options:

Correct Answer: y = -1/3x

Solution:

The slope of the given line is 3. The slope of the perpendicular line is -1/3. Thus, the equation is y = -1/3x.

What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the origin?

What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the origin?

Correct Answer: y = -1/3x

Step 1: Identify the slope of the given line. The equation is y = 3x + 4, so the slope (m) is 3.
Step 2: Find the slope of the line that is perpendicular to the given line. The slope of a perpendicular line is the negative reciprocal of the original slope. The negative reciprocal of 3 is -1/3.
Step 3: Since the line we want passes through the origin, we know that the y-intercept (b) is 0.
Step 4: Write the equation of the line using the slope and y-intercept. The equation is y = -1/3x.

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