Find the value of the definite integral ∫(0 to π) sin(x) dx. (2019)

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Question: Find the value of the definite integral ∫(0 to π) sin(x) dx. (2019)

Options:

Correct Answer: 2

Exam Year: 2019

Solution:

∫(0 to π) sin(x) dx = [-cos(x)] from 0 to π = [1 - (-1)] = 2.

Find the value of the definite integral ∫(0 to π) sin(x) dx. (2019)

Find the value of the definite integral ∫(0 to π) sin(x) dx. (2019)

Step 1: Identify the integral you need to solve: ∫(0 to π) sin(x) dx.
Step 2: Find the antiderivative of sin(x). The antiderivative is -cos(x).
Step 3: Write the expression for the definite integral using the antiderivative: [-cos(x)] from 0 to π.
Step 4: Evaluate the antiderivative at the upper limit (π): -cos(π) = -(-1) = 1.
Step 5: Evaluate the antiderivative at the lower limit (0): -cos(0) = -1.
Step 6: Subtract the lower limit result from the upper limit result: 1 - (-1) = 1 + 1 = 2.
Step 7: Conclude that the value of the definite integral ∫(0 to π) sin(x) dx is 2.

Definite Integral – The process of calculating the area under the curve of a function between two specified limits.
Trigonometric Functions – Understanding the properties and integrals of sine and cosine functions.
Fundamental Theorem of Calculus – Connecting differentiation and integration, particularly evaluating integrals using antiderivatives.