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Find the equation of the pair of lines represented by the equation x^2 - 4y^2 =
Find the equation of the pair of lines represented by the equation x^2 - 4y^2 = 0.
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Practice Questions
1 question
Q1
Find the equation of the pair of lines represented by the equation x^2 - 4y^2 = 0.
x = 2y, x = -2y
x = 4y, x = -4y
x = 0, y = 0
x = y, x = -y
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Factoring the equation gives (x - 2y)(x + 2y) = 0, which represents the lines x = 2y and x = -2y.
Questions & Step-by-step Solutions
1 item
Q
Q: Find the equation of the pair of lines represented by the equation x^2 - 4y^2 = 0.
Solution:
Factoring the equation gives (x - 2y)(x + 2y) = 0, which represents the lines x = 2y and x = -2y.
Steps: 7
Show Steps
Step 1: Start with the given equation: x^2 - 4y^2 = 0.
Step 2: Recognize that this equation is a difference of squares, which can be factored.
Step 3: Use the difference of squares formula: a^2 - b^2 = (a - b)(a + b). Here, a = x and b = 2y.
Step 4: Apply the formula to factor the equation: (x - 2y)(x + 2y) = 0.
Step 5: Set each factor equal to zero to find the lines: x - 2y = 0 and x + 2y = 0.
Step 6: Solve each equation for y: From x - 2y = 0, we get y = x/2; From x + 2y = 0, we get y = -x/2.
Step 7: The equations of the lines are y = x/2 and y = -x/2.
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