If the lines represented by the equation 5x^2 + 6xy + 5y^2 = 0 intersect at the

Practice Questions

Q1
If the lines represented by the equation 5x^2 + 6xy + 5y^2 = 0 intersect at the origin, what is the angle between them?
  1. 0 degrees
  2. 45 degrees
  3. 90 degrees
  4. 60 degrees

Questions & Step-by-Step Solutions

If the lines represented by the equation 5x^2 + 6xy + 5y^2 = 0 intersect at the origin, what is the angle between them?
Correct Answer: 45 degrees
  • Step 1: Identify the given equation, which is 5x^2 + 6xy + 5y^2 = 0.
  • Step 2: Recognize that this is a quadratic equation in x and y, representing two lines that intersect.
  • Step 3: Rewrite the equation in the standard form of a conic section to find the slopes of the lines.
  • Step 4: Factor the equation or use the quadratic formula to find the slopes (m1 and m2) of the lines.
  • Step 5: Use the formula tan(θ) = |(m1 - m2) / (1 + m1*m2)| to find the tangent of the angle θ between the two lines.
  • Step 6: Calculate the angle θ by taking the arctan of the value obtained in Step 5.
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