My Learning Cart

The equation x^2 - 2x + 1 = 0 has how many distinct roots?

Practice Questions

Q1
The equation x^2 - 2x + 1 = 0 has how many distinct roots?
  1. 0
  2. 1
  3. 2
  4. 3

Questions & Step-by-Step Solutions

The equation x^2 - 2x + 1 = 0 has how many distinct roots?
  • Step 1: Identify the equation given, which is x^2 - 2x + 1 = 0.
  • Step 2: Recognize that this is a quadratic equation in the form ax^2 + bx + c.
  • Step 3: Identify the coefficients: a = 1, b = -2, c = 1.
  • Step 4: Calculate the discriminant using the formula D = b^2 - 4ac.
  • Step 5: Substitute the values into the formula: D = (-2)^2 - 4(1)(1).
  • Step 6: Simplify the calculation: D = 4 - 4 = 0.
  • Step 7: Interpret the result: A discriminant of 0 means there is exactly one distinct root.
No concepts available.
Biology (School & UG)
Biology (School & UG)
Chemistry (School & UG)
Chemistry (School & UG)
Civil Engineering
Civil Engineering
Commerce & Accountancy
Commerce & Accountancy
Computer Science & IT
Computer Science & IT
Current Affairs & GK
Current Affairs & GK
Data Structures & Algorithms
Data Structures & Algorithms
eBooks
eBooks
Electrical & Electronics Engineering
Electrical & Electronics Engineering
English (School)
English (School)
General Aptitude
General Aptitude
General Knowledge
General Knowledge
General Knowledge & Current Affairs
General Knowledge & Current Affairs
Languages & Literature
Languages & Literature
Law & Legal Studies
Law & Legal Studies
Major Competitive Exams
Major Competitive Exams
Mathematics (School)
Mathematics (School)
Mechanical Engineering
Mechanical Engineering
Medical Science
Medical Science
Physics (School & Undergraduate)
Physics (School & Undergraduate)
Quantitative Aptitude & Reasoning
Quantitative Aptitude & Reasoning
Social Science (School)
Social Science (School)
Technical
Technical
Verbal and Reasoning
Verbal and Reasoning
Vocational & Skill Development
Vocational & Skill Development
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely