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What is the vertex of the quadratic function f(x) = 2x^2 - 8x + 5? (2021)

Practice Questions

1 question
Q1
What is the vertex of the quadratic function f(x) = 2x^2 - 8x + 5? (2021)
  1. (2, -3)
  2. (2, -7)
  3. (4, -3)
  4. (4, -7)

Questions & Step-by-step Solutions

1 item
Q
Q: What is the vertex of the quadratic function f(x) = 2x^2 - 8x + 5? (2021)
Solution: The vertex can be found using x = -b/(2a). Here, x = 8/(2*2) = 2. Substituting x = 2 into f(x) gives f(2) = -3, so the vertex is (2, -3).
Steps: 0

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