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A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of th

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Question: A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of the mixture is taken, how much of substance Y is there?

Options:

  1. 8 liters
  2. 2 liters
  3. 4 liters
  4. 6 liters

Correct Answer: 8 liters

Solution:

80% of 10 liters = 0.80 * 10 = 8 liters of substance Y.

A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of th

Practice Questions

Q1
A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of the mixture is taken, how much of substance Y is there?
  1. 8 liters
  2. 2 liters
  3. 4 liters
  4. 6 liters

Questions & Step-by-Step Solutions

A mixture contains 20% of substance X and 80% of substance Y. If 10 liters of the mixture is taken, how much of substance Y is there?
  • Step 1: Understand that the mixture has 20% of substance X and 80% of substance Y.
  • Step 2: Know that you are taking 10 liters of this mixture.
  • Step 3: To find out how much of substance Y is in the 10 liters, calculate 80% of 10 liters.
  • Step 4: Convert 80% to a decimal, which is 0.80.
  • Step 5: Multiply 0.80 by 10 liters: 0.80 * 10 = 8 liters.
  • Step 6: Conclude that there are 8 liters of substance Y in the 10 liters of mixture.
  • Percentage Calculation – Understanding how to calculate a percentage of a total quantity.
  • Mixture Composition – Recognizing the proportions of different substances in a mixture.
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