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A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is draw

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Question: A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is drawn at random, what is the probability that it is not blue?

Options:

  1. 0.5
  2. 0.6
  3. 0.7
  4. 0.8

Correct Answer: 0.7

Solution: 

Total balls = 3 + 2 + 5 = 10. Non-blue balls = 3 + 5 = 8. Probability = Non-blue balls / Total balls = 8/10 = 0.8.

A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is draw

Practice Questions

Q1
A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is drawn at random, what is the probability that it is not blue?
  1. 0.5
  2. 0.6
  3. 0.7
  4. 0.8

Questions & Step-by-Step Solutions

A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is drawn at random, what is the probability that it is not blue?
  • Step 1: Count the total number of balls in the box. There are 3 red balls, 2 blue balls, and 5 green balls.
  • Step 2: Add the number of red, blue, and green balls together: 3 + 2 + 5 = 10. So, the total number of balls is 10.
  • Step 3: Count the number of non-blue balls. Non-blue balls are red and green. There are 3 red balls and 5 green balls.
  • Step 4: Add the number of red and green balls together: 3 + 5 = 8. So, there are 8 non-blue balls.
  • Step 5: To find the probability of drawing a non-blue ball, divide the number of non-blue balls by the total number of balls: 8 / 10.
  • Step 6: Simplify the fraction 8 / 10 to get 0.8. This means the probability of drawing a non-blue ball is 0.8.
  • Probability – The likelihood of an event occurring, calculated as the ratio of favorable outcomes to total outcomes.
  • Counting Outcomes – Understanding how to count the total number of outcomes and favorable outcomes in a probability scenario.
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