A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is draw

A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is drawn at random, what is the probability that it is not blue?

A box contains 3 red balls, 2 blue balls, and 5 green balls. If one ball is drawn at random, what is the probability that it is not blue?

Step 1: Count the total number of balls in the box. There are 3 red balls, 2 blue balls, and 5 green balls.
Step 2: Add the number of red, blue, and green balls together: 3 + 2 + 5 = 10. So, the total number of balls is 10.
Step 3: Count the number of non-blue balls. Non-blue balls are red and green. There are 3 red balls and 5 green balls.
Step 4: Add the number of red and green balls together: 3 + 5 = 8. So, there are 8 non-blue balls.
Step 5: To find the probability of drawing a non-blue ball, divide the number of non-blue balls by the total number of balls: 8 / 10.
Step 6: Simplify the fraction 8 / 10 to get 0.8. This means the probability of drawing a non-blue ball is 0.8.

Probability – The likelihood of an event occurring, calculated as the ratio of favorable outcomes to total outcomes.
Counting Outcomes – Understanding how to count the total number of outcomes and favorable outcomes in a probability scenario.