Question: If a rectangle has a length that is twice its width and the perimeter is 48 cm, what is the area of the rectangle?
Options:
Correct Answer: 144 cm²
Solution:
Let width = w, then length = 2w. Perimeter = 2(length + width) = 48. Thus, 2(2w + w) = 48, leading to 6w = 48, so w = 8 cm. Area = length * width = 2w * w = 2*8*8 = 128 cm².