In a round-robin format, each team plays every other team once. If there are 8 t

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Question: In a round-robin format, each team plays every other team once. If there are 8 teams, how many games will be played?

Options:

Correct Answer: 28

Solution:

The number of games is calculated using the formula n(n-1)/2. For 8 teams, it is 8(7)/2 = 28.

In a round-robin format, each team plays every other team once. If there are 8 teams, how many games will be played?

In a round-robin format, each team plays every other team once. If there are 8 teams, how many games will be played?

Step 1: Understand that in a round-robin format, each team plays every other team exactly once.
Step 2: Identify the number of teams, which is 8 in this case.
Step 3: Use the formula for calculating the number of games: n(n-1)/2, where n is the number of teams.
Step 4: Substitute the number of teams into the formula: 8(8-1)/2.
Step 5: Calculate 8-1, which equals 7.
Step 6: Multiply 8 by 7, which equals 56.
Step 7: Divide 56 by 2, which equals 28.
Step 8: Conclude that a total of 28 games will be played.

Combinatorics – The question tests the understanding of combinations, specifically how to calculate the number of unique pairs (games) that can be formed from a set of teams.
Round-Robin Tournament Structure – Understanding the format of a round-robin tournament where each team plays every other team exactly once.