Evaluate ∫ from 0 to 2 of (x^2 + 2x + 1) dx.

Practice Questions

Q1
Evaluate ∫ from 0 to 2 of (x^2 + 2x + 1) dx.
  1. 4
  2. 5
  3. 6
  4. 7

Questions & Step-by-Step Solutions

Evaluate ∫ from 0 to 2 of (x^2 + 2x + 1) dx.
Correct Answer: 6
  • Step 1: Identify the function to integrate, which is (x^2 + 2x + 1).
  • Step 2: Find the antiderivative of the function. The antiderivative of x^2 is x^3/3, the antiderivative of 2x is x^2, and the antiderivative of 1 is x.
  • Step 3: Combine the antiderivatives to get the complete antiderivative: (x^3/3 + x^2 + x).
  • Step 4: Evaluate the antiderivative at the upper limit (2) and the lower limit (0).
  • Step 5: Calculate the value at the upper limit: (2^3/3 + 2^2 + 2) = (8/3 + 4 + 2).
  • Step 6: Calculate the value at the lower limit: (0^3/3 + 0^2 + 0) = 0.
  • Step 7: Subtract the lower limit value from the upper limit value: (8/3 + 4 + 2) - 0 = (8/3 + 4 + 2).
  • Step 8: Simplify the expression: 4 + 2 = 6, so the final result is 6.
  • Definite Integral – The process of calculating the area under a curve defined by a function over a specific interval.
  • Polynomial Integration – Applying the power rule for integration to polynomial functions.
  • Fundamental Theorem of Calculus – Connecting differentiation and integration, allowing evaluation of definite integrals using antiderivatives.
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