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If a mixture contains 40% alcohol and 60% water, how much water is present in 50
If a mixture contains 40% alcohol and 60% water, how much water is present in 50 liters of the mixture?
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Q1
If a mixture contains 40% alcohol and 60% water, how much water is present in 50 liters of the mixture?
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60% of 50 liters = 0.6 * 50 = 30 liters of water.
Questions & Step-by-step Solutions
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Q
Q: If a mixture contains 40% alcohol and 60% water, how much water is present in 50 liters of the mixture?
Solution:
60% of 50 liters = 0.6 * 50 = 30 liters of water.
Steps: 6
Show Steps
Step 1: Understand that the mixture is made up of 40% alcohol and 60% water.
Step 2: Know that we need to find out how much water is in 50 liters of this mixture.
Step 3: Calculate 60% of 50 liters to find the amount of water.
Step 4: Convert 60% to a decimal, which is 0.6.
Step 5: Multiply 0.6 by 50 liters: 0.6 * 50 = 30 liters.
Step 6: Conclude that there are 30 liters of water in the mixture.
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