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If a mixture contains 40% alcohol and 60% water, how much water is present in 50

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Question: If a mixture contains 40% alcohol and 60% water, how much water is present in 50 liters of the mixture?

Options:

  1. 20 liters
  2. 30 liters
  3. 25 liters
  4. 35 liters

Correct Answer: 30 liters

Solution: 

60% of 50 liters = 0.6 * 50 = 30 liters of water.

If a mixture contains 40% alcohol and 60% water, how much water is present in 50

Practice Questions

Q1
If a mixture contains 40% alcohol and 60% water, how much water is present in 50 liters of the mixture?
  1. 20 liters
  2. 30 liters
  3. 25 liters
  4. 35 liters

Questions & Step-by-Step Solutions

If a mixture contains 40% alcohol and 60% water, how much water is present in 50 liters of the mixture?
  • Step 1: Understand that the mixture is made up of 40% alcohol and 60% water.
  • Step 2: Know that we need to find out how much water is in 50 liters of this mixture.
  • Step 3: Calculate 60% of 50 liters to find the amount of water.
  • Step 4: Convert 60% to a decimal, which is 0.6.
  • Step 5: Multiply 0.6 by 50 liters: 0.6 * 50 = 30 liters.
  • Step 6: Conclude that there are 30 liters of water in the mixture.
  • Percentage Calculation – Understanding how to calculate a percentage of a total quantity.
  • Mixture Composition – Recognizing the components of a mixture and their respective proportions.
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