For the function f(x) = x^2 - 4x + 5, find the minimum value.

Practice Questions

1 question
Q1
For the function f(x) = x^2 - 4x + 5, find the minimum value.
  1. 1
  2. 2
  3. 3
  4. 4

Questions & Step-by-step Solutions

1 item
Q
Q: For the function f(x) = x^2 - 4x + 5, find the minimum value.
Solution: The vertex occurs at x = 2. f(2) = 2^2 - 4*2 + 5 = 1, which is the minimum value.
Steps: 7

Related Questions

Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely