Determine the critical points of the function f(x) = x^3 - 6x^2 + 9x.

Practice Questions

Q1
Determine the critical points of the function f(x) = x^3 - 6x^2 + 9x.
  1. (0, 0)
  2. (1, 4)
  3. (2, 0)
  4. (3, 0)

Questions & Step-by-Step Solutions

Determine the critical points of the function f(x) = x^3 - 6x^2 + 9x.
Correct Answer: x = 1 and x = 3
  • Step 1: Start with the function f(x) = x^3 - 6x^2 + 9x.
  • Step 2: Find the derivative of the function, which is f'(x). The derivative tells us the slope of the function.
  • Step 3: Calculate the derivative: f'(x) = 3x^2 - 12x + 9.
  • Step 4: Set the derivative equal to zero to find critical points: 3x^2 - 12x + 9 = 0.
  • Step 5: Factor the equation: (x - 1)(x - 3) = 0.
  • Step 6: Solve for x by setting each factor equal to zero: x - 1 = 0 gives x = 1, and x - 3 = 0 gives x = 3.
  • Step 7: The critical points are x = 1 and x = 3.
  • Critical Points – Critical points are values of x where the derivative of the function is zero or undefined, indicating potential local maxima, minima, or points of inflection.
  • Derivative Calculation – Finding the derivative of a function is essential for determining critical points.
  • Factoring Quadratics – Factoring the derivative to find roots is a key skill in solving for critical points.
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