What is the value of the polynomial p(x) = 3x^2 - 4x + 1 at x = 2?

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Question: What is the value of the polynomial p(x) = 3x^2 - 4x + 1 at x = 2?

Options:

Correct Answer: 5

Solution:

Substituting x = 2 into the polynomial gives p(2) = 3(2^2) - 4(2) + 1 = 12 - 8 + 1 = 5.

What is the value of the polynomial p(x) = 3x^2 - 4x + 1 at x = 2?

What is the value of the polynomial p(x) = 3x^2 - 4x + 1 at x = 2?

Step 1: Identify the polynomial p(x) = 3x^2 - 4x + 1.
Step 2: Substitute x = 2 into the polynomial. This means we replace every x in the polynomial with 2.
Step 3: Calculate 2^2, which is 4.
Step 4: Multiply 3 by 4 (from Step 3) to get 12.
Step 5: Multiply -4 by 2 to get -8.
Step 6: Now, combine the results: 12 (from Step 4) - 8 (from Step 5) + 1.
Step 7: First, do 12 - 8, which equals 4.
Step 8: Finally, add 1 to 4 to get 5.

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