Question: If the sum of the first n terms of a geometric progression is given by S_n = a(1 - r^n) / (1 - r), what happens to S_n as n approaches infinity when |r| < 1?
Options:
Correct Answer: S_n approaches a/(1-r)
Solution:
As n approaches infinity and |r| < 1, r^n approaches 0, thus S_n approaches a/(1-r).