Question: If the sum of the first n terms of an arithmetic progression is given by S_n = 3n^2 + 2n, what is the common difference of the sequence?
Options:
Correct Answer: 3
Solution:
The common difference can be found by calculating S_n - S_(n-1). S_n = 3n^2 + 2n and S_(n-1) = 3(n-1)^2 + 2(n-1). Simplifying gives the common difference as 6.