If the sum of the first n terms of an arithmetic progression is given by S_n = 3n^2 + 2n, what is the common difference of the sequence?
Practice Questions
1 question
Q1
If the sum of the first n terms of an arithmetic progression is given by S_n = 3n^2 + 2n, what is the common difference of the sequence?
3
4
5
6
The common difference can be found by calculating S_n - S_(n-1). S_n = 3n^2 + 2n and S_(n-1) = 3(n-1)^2 + 2(n-1). Simplifying gives the common difference as 6.
Questions & Step-by-step Solutions
1 item
Q
Q: If the sum of the first n terms of an arithmetic progression is given by S_n = 3n^2 + 2n, what is the common difference of the sequence?
Solution: The common difference can be found by calculating S_n - S_(n-1). S_n = 3n^2 + 2n and S_(n-1) = 3(n-1)^2 + 2(n-1). Simplifying gives the common difference as 6.
