Question: In a double-elimination tournament, a team is eliminated after losing two matches. If there are 8 teams, what is the minimum number of matches needed to declare a winner?
Options:
Correct Answer: 14
Solution:
In a double-elimination tournament, the minimum number of matches needed is 2n - 2, where n is the number of teams. For 8 teams, it is 2(8) - 2 = 14.