In a double-elimination tournament, a team is eliminated after losing two matche
Practice Questions
Q1
In a double-elimination tournament, a team is eliminated after losing two matches. If there are 8 teams, what is the minimum number of matches needed to declare a winner?
14
15
16
13
Questions & Step-by-Step Solutions
In a double-elimination tournament, a team is eliminated after losing two matches. If there are 8 teams, what is the minimum number of matches needed to declare a winner?
Step 1: Understand that in a double-elimination tournament, a team is eliminated after losing 2 matches.
Step 2: Know that there are 8 teams in this tournament.
Step 3: Use the formula for the minimum number of matches needed, which is 2n - 2, where n is the number of teams.
Step 4: Substitute the number of teams (n = 8) into the formula: 2(8) - 2.
Step 5: Calculate 2 times 8, which equals 16.
Step 6: Subtract 2 from 16, which gives you 14.
Step 7: Conclude that the minimum number of matches needed to declare a winner is 14.
