What is the maximum number of iterations needed to find an element in an array o

₹0.0

Question: What is the maximum number of iterations needed to find an element in an array of size 32 using binary search?

Options:

Correct Answer: 7

Solution:

The maximum number of iterations is log2(32) = 5, but since we count from 0, it can take up to 6 iterations.

What is the maximum number of iterations needed to find an element in an array of size 32 using binary search?

What is the maximum number of iterations needed to find an element in an array of size 32 using binary search?

Step 1: Understand that binary search works by repeatedly dividing the array in half.
Step 2: Know that the maximum number of iterations needed to find an element is determined by how many times you can divide the array until you reach one element.
Step 3: Calculate log2(32). This means you are finding how many times you can divide 32 by 2 until you get to 1.
Step 4: Calculate log2(32). Since 32 is 2 raised to the power of 5 (because 2^5 = 32), log2(32) = 5.
Step 5: Remember that we start counting from 0. So, if it takes 5 divisions to reach 1, the total number of iterations is 5 + 1 = 6.
Step 6: Conclude that the maximum number of iterations needed to find an element in an array of size 32 using binary search is 6.

No concepts available.