Question: What happens to the search space in each iteration of binary search?
Options:
It doubles
It halves
It remains the same
It increases linearly
Correct Answer: It halves
Solution:
In each iteration of binary search, the search space is halved, which contributes to its logarithmic time complexity.
What happens to the search space in each iteration of binary search?
Practice Questions
Q1
What happens to the search space in each iteration of binary search?
It doubles
It halves
It remains the same
It increases linearly
Questions & Step-by-Step Solutions
What happens to the search space in each iteration of binary search?
Step 1: Start with a sorted list of numbers.
Step 2: Identify the middle element of the list.
Step 3: Compare the middle element with the target number you are searching for.
Step 4: If the middle element is equal to the target, you have found the number.
Step 5: If the middle element is less than the target, discard the left half of the list (including the middle element).
Step 6: If the middle element is greater than the target, discard the right half of the list (including the middle element).
Step 7: Repeat steps 2 to 6 with the new, smaller list (the remaining half).
Step 8: Each time you repeat the process, the search space (the list you are looking at) gets smaller, specifically halving in size.
Binary Search – A search algorithm that finds the position of a target value within a sorted array by repeatedly dividing the search interval in half.
Search Space – The portion of the array that is being considered for the search at any given iteration.
Logarithmic Time Complexity – The time complexity of binary search, which is O(log n), indicating that the number of iterations grows logarithmically with the size of the input.
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