What is the worst-case scenario for the number of comparisons made by binary sea

What is the worst-case scenario for the number of comparisons made by binary search on an array of size n?

What is the worst-case scenario for the number of comparisons made by binary search on an array of size n?

Step 1: Understand what binary search is. It is a method to find an element in a sorted array by repeatedly dividing the search interval in half.
Step 2: Know that binary search starts by looking at the middle element of the array.
Step 3: If the middle element is the target, the search is done. If not, it decides whether to search the left half or the right half of the array.
Step 4: Each time you divide the array, you reduce the number of elements to search by half.
Step 5: The worst-case scenario occurs when you keep dividing the array until you have only one element left to check.
Step 6: The number of times you can divide n elements in half until you reach 1 is log base 2 of n, which is written as log n.
Step 7: Therefore, in the worst case, binary search makes log n comparisons.

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